In signal processing, the instantaneous power P P\,P of a specific modulated wave relative to its phase ϕ \phi\,ϕ is modeled by the function:
P(ϕ)=(5cosϕ−2sinϕ)2 P(\phi) = (5\cos \phi - 2\sin \phi)^2 P(ϕ)=(5cosϕ−2sinϕ)2Determine the indefinite integral of the power function with respect to the phase, giving your answer in its simplest form:
∫P(ϕ) dϕ \int P(\phi) \, d\phi ∫P(ϕ)dϕ