In this question, use g=9.8 m s−2g = 9.8 \text{ m s}^{-2}g=9.8 m s−2.
A precision sensor module is dragged across a rough horizontal laboratory floor. A horizontal tension of magnitude FFF newtons is applied to the module by a robotic arm.
The module moves with a constant acceleration of 0.75 m s−20.75 \text{ m s}^{-2}0.75 m s−2.
The sensor module has a weight of 4.41 N4.41 \text{ N}4.41 N.
The only resistance to motion is the friction between the module and the floor.
The coefficient of friction between the module and the floor is 0.220.220.22.
Find FFF.
136 exam-style questions on CCEA A Level Maths 2.3 Forces and Newton's laws, covering 2.3.1 Forces and Newton's laws, 2.3.2 Forces and Newton's laws, 2.3.3 Forces and Newton's laws, 2.3.4 Forces and Newton's laws, 2.3.5 Forces and Newton's laws, 2.3.6 Forces and Newton's laws, 2.3.7 Forces and Newton's laws, 2.3.8 Forces and Newton's laws, 2.3.9 Forces and Newton's laws, 2.3.10 Forces and Newton's laws, 2.3.11 Forces and Newton's laws, 2.3.12 Forces and Newton's laws, and 2.3 Forces and Newton's laws. Each one has a worked solution and a mark scheme showing where the marks go.