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1.5.5 Exponentials and logarithms

Hard
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Question 7

For a>0a>0a>0, a≠1a\ne1a=1, x>0 x>0\,x>0 and y>0y>0y>0, prove that log⁡a(xy)=log⁡ax+log⁡ay\log_a(xy)=\log_ax+\log_ayloga​(xy)=loga​x+loga​y.

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Markscheme

1.5.5 Exponentials and logarithms Questions

  1. A Level
  2. /Maths
  3. /1.5.5 Exponentials and logarithms

8 exam-style questions on CCEA A Level Maths 1.5.5 Exponentials and logarithms. Each one has a worked solution and a mark scheme showing where the marks go.

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