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1.6 Differentiation

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Question 23

The velocity, vvv m s−1\text{m s}^{-1}m s−1, of a research drone at time ttt seconds (t>0t > 0t>0) is defined such that its acceleration aaa follows the equation:

a=dvdt=12t+kt3+10 a = \frac{dv}{dt} = \frac{12}{\sqrt{t}} + \frac{k}{t^3} + 10 a=dtdv​=t​12​+t3k​+10

where kkk is a constant.

It is observed that the rate of change of the drone's acceleration is zero at the instant where t=4t = 4t=4.

a.

Determine the value of kkk.

[4]
b.

Given that the drone's velocity is 100100100 m s−1\text{m s}^{-1}m s−1 when t=1t = 1t=1, find an expression for vvv in terms of ttt, giving each term in simplest form.

[4]

1.6 Differentiation Questions

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