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1.1.10 Algebra and functions

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Question 37

Given that

g(x)=4x2−13x+13x−3 g(x) = \frac{4x^2 - 13x + 13}{x - 3} g(x)=x−34x2−13x+13​
a.

Write g(x)g(x)g(x) in the form

Ax+B+Cx−3 Ax + B + \frac{C}{x - 3} Ax+B+x−3C​

where AAA, BBB, and CCC are integers to be found.

[4]
b.

Hence use algebraic integration to show that

∫46g(x) dx=α+βln⁡3 \int_{4}^{6} g(x) \, dx = \alpha + \beta \ln 3 ∫46​g(x)dx=α+βln3

where α\alphaα and betabetabeta are integers to be found.

[4]

1.1.10 Algebra and functions Questions

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