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1.8.9 Trigonometry in context

The component adjacent to the given angle uses [     ]; the component opposite the angle uses sine.

A

Tsin⁡40∘=120T\sin40^\circ=120Tsin40∘=120, so T≈187 N\mathbf{T\approx187\text{ N}}T≈187 N.

B

The component adjacent to the given angle uses cosine; the component opposite the angle uses sine.

C

P=187cos⁡40∘≈143 NP=187\cos40^\circ\approx\mathbf{143\text{ N}}P=187cos40∘≈143 N.

D

Both components are negative.

1.8.9 Trigonometry in context Flashcards

  1. A Level
  2. /Maths
  3. /1.8.9 Trigonometry in context

Flashcards for AQA A Level Maths 1.8.9 Trigonometry in context, covering the key formulae, methods and definitions you need to recall for Paper 1, Paper 2 and Paper 3. 23 cards, matched to the AQA A Level Maths (7357) specification. Recall questions account for roughly 50% of marks at A Level Maths, so these target the marks you can secure before the paper starts.