A mechanical linkage is designed such that its angle of rotation, β\betaβ, in degrees, satisfies the equilibrium condition:
5tan(β−60∘)=2cos(β−60∘) 5 \tan(\beta - 60^\circ) = 2 \cos(\beta - 60^\circ) 5tan(β−60∘)=2cos(β−60∘)Find all possible values of β\betaβ in the interval −180∘<β≤180∘-180^\circ < \beta \le 180^\circ−180∘<β≤180∘. Give your answers to one decimal place where appropriate.
42 exam-style questions on AQA A Level Maths 1.8.7 Solving trigonometric equations. Each one has a worked solution and a mark scheme showing where the marks go.