The yield efficiency of a thermal generator, E(τ)E(\tau)E(τ), is given by the function
E(τ)=42τ2−17τ+156τ−5 E(\tau) = \frac{42\tau^2 - 17\tau + 15}{6\tau - 5} E(τ)=6τ−542τ2−17τ+15where τ>1\tau > 1τ>1 is the operating temperature factor. This expression can be rewritten in the form Aτ+B+C6τ−5A\tau + B + \frac{C}{6\tau - 5}Aτ+B+6τ−5C.
State the value of AAA.
Circle your answer:
671542 6 \quad\quad 7 \quad\quad 15 \quad\quad 42 671542
