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1.5.6 Polynomials and rational expressions

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Question 41

A chemical engineer models the rate of heat loss H(T)H(T)H(T), in kilowatts per degree Celsius, from a specific pressurized vessel using the formula

H(T)=2T2−3T−7T−4,T>4 H(T) = \frac{2T^2 - 3T - 7}{T - 4}, \quad T > 4 H(T)=T−42T2−3T−7​,T>4

where TTT is the temperature of the vessel in degrees Celsius.

a.

Write H(T)H(T)H(T) in the form

AT+B+CT−4 AT + B + \frac{C}{T - 4} AT+B+T−4C​

where AAA, BBB, and CCC are integers to be found.

[3]
b.

Hence use algebraic integration to show that the total heat loss between temperature T=5T = 5T=5 and T=7T = 7T=7, given by ∫57H(T) dT\int_{5}^{7} H(T) \, dT∫57​H(T)dT, is equal to

α+βln⁡3 \alpha + \beta \ln 3 α+βln3

where α\alphaα and β\betaβ are integers to be found.

[4]

1.5.6 Polynomials and rational expressions Questions

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  3. /1.5.6 Polynomials and rational expressions