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What does a negative horizontal component indicate?
A
The positive reference angle is α=tan−1(∣yx∣)\boxed{\alpha=\tan^{-1}\left(\left|\frac{y}{x}\right|\right)}α=tan−1(xy).
B
Movement to the left.
C
For a vector in the second quadrant, its direction is θ=180∘−α\boxed{\theta=180^\circ-\alpha}θ=180∘−α.
D
(−5)2=25(-5)^2=25(−5)2=25, whereas −52=−25-5^2=-25−52=−25.
Card 1 of 25
1.13.2 Magnitude and direction of a vector Flashcards
25 flashcards on AQA A Level Maths 1.13.2 Magnitude and direction of a vector: the key formulae, methods and definitions you need to recall for Paper 1, Paper 2 and Paper 3.