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1.13 J: Vectors

1.13 J: Vectors

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Question 22

In triangle XYZXYZXYZ, XY⃗=−2i+6j−3k\vec{XY} = -2\mathbf{i} + 6\mathbf{j} - 3\mathbf{k}XY=−2i+6j−3k, XZ⃗=4i+j+7k\vec{XZ} = 4\mathbf{i} + \mathbf{j} + 7\mathbf{k}XZ=4i+j+7k

a.

Find the vector YZ→\overrightarrow{YZ}YZ

[3]
b.

Find the length of the line XYXYXY

[3]
Markscheme

1.13 J: Vectors Questions

  1. A Level
  2. /Maths
  3. /1.13 J: Vectors

168 exam-style questions on AQA A Level Maths 1.13 J: Vectors, covering 1.13.1 Vectors in two and three dimensions, 1.13.2 Magnitude and direction of a vector, 1.13.3 Vector arithmetic, 1.13.4 Position vectors, and 1.13.5 Vectors to solve problems. Each one has a worked solution and a mark scheme showing where the marks go.

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