Use the substitution u=6−exu = 6 - e^xu=6−ex to find ∫0ln2ex6−exdx\displaystyle \int_0^{\ln 2} \frac{e^x}{6 - e^x} dx∫0ln26−exexdx
119 exam-style questions on AQA A Level Maths 1.11.5 Integration by substitution and by parts (A-level only). Each one has a worked solution and a mark scheme showing where the marks go.