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1.11.2 Integrating standard functions

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Question 64

The curve C C\,C has equation y=f(x)y = f(x)y=f(x) where x>0x > 0x>0.

Given that

  • f′(x)=(5x+2)2x2xf'(x) = \dfrac{(5\sqrt{x} + 2)^2}{x^2\sqrt{x}}f′(x)=x2x​(5x​+2)2​
  • the point P(4,−10)P(4, -10)P(4,−10) lies on CCC
a.

(i) Find the value of the gradient of the curve at PPP.

(ii) Hence find the equation of the tangent to C C\,C at PPP, giving your answer in the form ax+by+c=0ax + by + c = 0ax+by+c=0, where aaa, b b\,b and c c\,c are integers to be found.

[4]
b.

Find f(x)f(x)f(x), simplifying your answer.

[6]

1.11.2 Integrating standard functions Questions

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