A prototype high-pressure vessel's volume V V\,V changes with respect to the internal pressure ppp (where p>0p > 0p>0) according to the rate:
dVdp=8p3−3p2p2 \frac{dV}{dp} = \frac{8p^3 - 3\sqrt{p}}{2p^2} dpdV=2p28p3−3pDetermine the general expression for V V\,V in terms of ppp, giving your answer in its simplest form.