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1.11.2 Integrating standard functions

1.11.2 Integrating standard functions

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Question 87

The curve C C\,C has equation

y=184(2x−k),x≠k2 y = \frac{18}{4(2x - k)}, \quad x \not= \frac{k}{2} y=4(2x−k)18​,x=2k​

where k k\,k is a positive constant and k≠2k \neq 2k=2.

a.

Find dydx\displaystyle \frac{dy}{dx}dxdy​ giving your answer in simplest form in terms of kkk.

[2]
b.

The point P P\,P with x x\,x coordinate 1 lies on CCC. Given that the gradient of the curve at P P\,P is -9, find the two possible values of kkk.

[3]
c.

Given also that k<2k < 2k<2, find the equation of the normal to C C\,C at PPP, writing your answer in the form ax+by+c=0ax + by + c = 0ax+by+c=0, where a,b a, b\,a,b and c c\,c are integers to be found.

[3]
d.

Show, using algebraic integration, that

∫13184(2x−k) dx=λln⁡(5) \int_{1}^{3} \frac{18}{4(2x - k)} \, dx = \lambda \ln(5) ∫13​4(2x−k)18​dx=λln(5)

where λ \lambda\,λ is a constant to be found.

[3]
Markscheme

1.11.2 Integrating standard functions Questions

  1. A Level
  2. /Maths
  3. /1.11.2 Integrating standard functions

139 exam-style questions on AQA A Level Maths 1.11.2 Integrating standard functions. Each one has a worked solution and a mark scheme showing where the marks go.

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