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1.6.1 Equation of a straight line

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Question 7
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The line l1 l_1\,l1​ has the equation 2x−3y−4=02x - 3y - 4 = 02x−3y−4=0 The line l2 l_2\,l2​ is perpendicular to l1 l_1\,l1​ and passes through the point (4,−1)(4, -1)(4,−1)

Find an equation for l2 l_2\,l2​ in the form ax+by+c=0ax + by + c = 0ax+by+c=0

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1.6.1 Equation of a straight line Questions

  1. A Level
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  3. /1.6.1 Equation of a straight line