Card 1 of 23
For A(x1,y1)A(x_1,y_1)A(x1,y1) and B(x2,y2)B(x_2,y_2)B(x2,y2), AB=AB=AB= [...]\text{[...]}[...].
The midpoint of ABABAB is (x1+x22,y1+y22)\left(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2}\right)(2x1+x2,2y1+y2).
90∘90^\circ90∘
The tangent is vertical.
For A(x1,y1)A(x_1,y_1)A(x1,y1) and B(x2,y2)B(x_2,y_2)B(x2,y2), AB=AB=AB= (x2−x1)2+(y2−y1)2\boxed{\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}}(x2−x1)2+(y2−y1)2.
The midpoint of ABABAB is (x1+x22,y1+y22)\left(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2}\right)(2x1+x2,2y1+y2).
(x−4)2+(y+1)2=25(x-4)^2+(y+1)^2=25(x−4)2+(y+1)2=25
Card 1 of 23
1.6.2 Coordinate geometry of the circle Flashcards
23 flashcards on AQA A Level Maths 1.6.2 Coordinate geometry of the circle: the key formulae, methods and definitions you need to recall for Paper 1, Paper 2 and Paper 3.