A precision thermal probe uses a linear scaling function HHH to map a raw voltage vvv to a temperature reading H(v)H(v)H(v), defined by:
H(v)=11v−214 H(v) = \frac{11v - 21}{4} H(v)=411v−21A technician identifies a specific voltage where the probe's output is identical to the output of the inverse scaling function H−1H^{-1}H−1 applied to that same voltage.
Solve the equation:
H(v)=H−1(v) H(v) = H^{-1}(v) H(v)=H−1(v)Select your answer from the options below:
v=−3v = -3v=−3
v=1v = 1v=1
v=3v = 3v=3
v=7v = 7v=7
532 exam-style questions on AQA A Level Maths 1.5 B: Algebra and functions, covering 1.5.1 Laws of indices, 1.5.2 Surds, 1.5.3 Quadratic functions, 1.5.4 Simultaneous equations, 1.5.5 Linear and quadratic inequalities, 1.5.6 Polynomials and rational expressions, 1.5.7 Graphs of functions and proportion, 1.5.8 Composite and inverse functions (A-level only), 1.5.9 Transformations of graphs, 1.5.10 Partial fractions (A-level only), and 1.5.11 Functions in modelling (A-level only). Each one has a worked solution and a mark scheme showing where the marks go.