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1.10.3 Applications of differentiation

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Question 17

A curve CCC has equation

y=2x3−15x+kx,x>0 y = 2x^3 - 15x + \frac{k}{x}, \quad x > 0 y=2x3−15x+xk​,x>0

where kkk is a constant. The point PPP with xxx-coordinate 111 lies on CCC. Given that PPP is a stationary point of CCC:

a.

show that k=−9k = -9k=−9.

[3]
b.

Determine the nature of the stationary point at PPP, justifying your answer.

[3]
c.

The curve CCC has a second stationary point.

Using algebra, find the xxx-coordinate of this second stationary point.

[4]

1.10.3 Applications of differentiation Questions

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