A student adds 25.0 cm3 of 0.120 mol dm-3 hydrochloric acid (HCl\text{HCl}HCl) to 75.0 cm3 of 0.080 mol dm-3 sodium hydroxide (NaOH\text{NaOH}NaOH).
What is the pH of the resulting mixture at 298 K?
[Kw=1.00×10−14 mol2 dm−6K_{\text{w}} = 1.00 \times 10^{-14}\text{ mol}^2\text{ dm}^{-6}Kw=1.00×10−14 mol2 dm−6 at 298 K]
1.521.521.52
11.4811.4811.48
12.4812.4812.48
12.7812.7812.78
