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Rates, equilibrium and pH

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Question 12

The rate of decomposition of a gaseous air pollutant was studied at various temperatures. A plot of ln⁡k \ln k\,lnk against 1T\displaystyle \frac{1}{T}T1​ (where T T\,T is in K\text{K}K) yielded a straight line with a gradient of -1.15 × 104 K.

What is the activation energy, EaE_{\text{a}}Ea​, for this decomposition reaction in kJ mol−1\text{kJ mol}^{-1}kJ mol−1? (Use gas constant R=8.314 J K−1 mol−1R = 8.314\text{ J K}^{-1}\text{ mol}^{-1}R=8.314 J K−1 mol−1)

+1.38+1.38+1.38

+95.6+95.6+95.6

−95.6-95.6−95.6

+9.56×104+9.56 \times 10^4+9.56×104

Rates, equilibrium and pH Questions

  1. A Level
  2. /Chemistry
  3. /Rates, equilibrium and pH