The equation for the complete combustion of liquid diethyl ether, C4H10O(l)\text{C}_4\text{H}_{10}\text{O(l)}C4H10O(l), is shown below:
C4H10O(l)+6O2(g)→4CO2(g)+5H2O(l) \text{C}_4\text{H}_{10}\text{O(l)} + 6\text{O}_2\text{(g)} \rightarrow 4\text{CO}_2\text{(g)} + 5\text{H}_2\text{O(l)} C4H10O(l)+6O2(g)→4CO2(g)+5H2O(l)Standard enthalpy changes of formation, ΔfH⊖\Delta_{\text{f}}H^{\ominus}ΔfH⊖, are given in the table below:
SubstanceC4H10O(l)CO2(g)H2O(l)ΔfH⊖ / kJ mol−1−272−394−286 \begin{array}{|c|c|c|c|} \hline \text{Substance} & \text{C}_4\text{H}_{10}\text{O(l)} & \text{CO}_2\text{(g)} & \text{H}_2\text{O(l)} \\ \hline \Delta_{\text{f}}H^{\ominus}\text{ / kJ mol}^{-1} & -272 & -394 & -286 \\ \hline \end{array} SubstanceΔfH⊖ / kJ mol−1C4H10O(l)−272CO2(g)−394H2O(l)−286Calculate the standard enthalpy of combustion, in kJ mol−1\text{kJ mol}^{-1}kJ mol−1, for diethyl ether.
