The equation for the reaction of barium hydroxide with hydrochloric acid is shown below:
Ba(OH)2(aq)+2HCl(aq)→BaCl2(aq)+2H2O(l) \text{Ba(OH)}_2(\text{aq}) + 2\text{HCl}(\text{aq}) \rightarrow \text{BaCl}_2(\text{aq}) + 2\text{H}_2\text{O}(\text{l}) Ba(OH)2(aq)+2HCl(aq)→BaCl2(aq)+2H2O(l)A volume of 80.0 cm3 of 0.250 mol dm-3 Ba(OH)2\text{Ba(OH)}_2Ba(OH)2 is reacted with excess HCl\text{HCl}HCl. The heat energy released is 2.256 kJ.
What is the standard enthalpy change of neutralisation, in kJ mol−1\text{kJ mol}^{-1}kJ mol−1?
−112.8-112.8−112.8
−56.4-56.4−56.4
+56.4+56.4+56.4
−225.6-225.6−225.6
