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Question 22

Bond enthalpies are given in the table below:

BondBond enthalpy / kJ mol−1\text{kJ mol}^{-1}kJ mol−1
N≡N\text{N}\equiv\text{N}N≡N+945
H−H\text{H}-\text{H}H−H+436
N−H\text{N}-\text{H}N−H+391

What is the enthalpy change, in kJ mol−1\text{kJ mol}^{-1}kJ mol−1, for the reaction below?

N2(g)+3H2(g)→2NH3(g) \text{N}_2(\text{g}) + 3\text{H}_2(\text{g}) \rightarrow 2\text{NH}_3(\text{g}) N2​(g)+3H2​(g)→2NH3​(g)

−1080 kJ mol−1-1080\text{ kJ mol}^{-1}−1080 kJ mol−1

−93 kJ mol−1-93\text{ kJ mol}^{-1}−93 kJ mol−1

+93 kJ mol−1+93\text{ kJ mol}^{-1}+93 kJ mol−1

−186 kJ mol−1-186\text{ kJ mol}^{-1}−186 kJ mol−1

Physical chemistry Questions

  1. A Level
  2. /Chemistry
  3. /Physical chemistry