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Question 4

The reaction between propanone and iodine in acidic conditions is zero-order with respect to iodine:

CH3COCH3(aq)+I2(aq)→H+(aq)CH3COCH2I(aq)+H+(aq)+I−(aq) \text{CH}_3\text{COCH}_3(\text{aq}) + \text{I}_2(\text{aq}) \xrightarrow{\text{H}^+(\text{aq})} \text{CH}_3\text{COCH}_2\text{I}(\text{aq}) + \text{H}^+(\text{aq}) + \text{I}^-(\text{aq}) CH3​COCH3​(aq)+I2​(aq)H+(aq)​CH3​COCH2​I(aq)+H+(aq)+I−(aq)

Which graph correctly represents how the concentration of iodine, [I2][\text{I}_2][I2​], changes with time during the reaction when iodine is the limiting reactant?

Four concentration-time graphs labeled Graph A, Graph B, Graph C, and Graph D.

Graph A

Graph B

Graph C

Graph D

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  1. A Level
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