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Chemical equilibrium

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Question 17

Ethyl methanoate, HCOOCH2CH3\text{HCOOCH}_2\text{CH}_3HCOOCH2​CH3​, is a volatile ester used as a flavoring agent with a characteristic rum-like odor. It can be prepared by reacting methanoic acid with ethanol in an aqueous equilibrium mixture:

HCOOH(aq)+CH3CH2OH(aq)⇌HCOOCH2CH3(aq)+H2O(l)Kc=0.75 dm3 mol−1 \text{HCOOH}(\text{aq}) + \text{CH}_3\text{CH}_2\text{OH}(\text{aq}) \rightleftharpoons \text{HCOOCH}_2\text{CH}_3(\text{aq}) + \text{H}_2\text{O}(\text{l}) \quad K_c = 0.75 \text{ dm}^3 \text{ mol}^{-1} HCOOH(aq)+CH3​CH2​OH(aq)⇌HCOOCH2​CH3​(aq)+H2​O(l)Kc​=0.75 dm3 mol−1

A 750 cm3750 \text{ cm}^3750 cm3 equilibrium mixture contains concentrations of 0.500 mol dm−30.500 \text{ mol dm}^{-3}0.500 mol dm−3 HCOOH(aq)\text{HCOOH}(\text{aq})HCOOH(aq) and 0.800 mol dm−30.800 \text{ mol dm}^{-3}0.800 mol dm−3 CH3CH2OH(aq)\text{CH}_3\text{CH}_2\text{OH}(\text{aq})CH3​CH2​OH(aq).

Calculate the amount, in mol, of ethyl methanoate in the equilibrium mixture.

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Chemical equilibrium Questions

  1. A Level
  2. /Chemistry
  3. /Chemical equilibrium