This question is about oxides of organic compounds and sulfur.
(a) An investigation is carried out on the equilibrium system shown below:
2CH3COOH(g)⇌(CH3COOH)2(g)ΔH=−58.2 kJ mol−1 2\text{CH}_3\text{COOH}(\text{g}) \rightleftharpoons (\text{CH}_3\text{COOH})_2(\text{g}) \quad \Delta H = -58.2\text{ kJ mol}^{-1} 2CH3COOH(g)⇌(CH3COOH)2(g)ΔH=−58.2 kJ mol−1A sealed flask containing 8.00 moles8.00\text{ moles}8.00 moles of CH3COOH(g)\text{CH}_3\text{COOH}(\text{g})CH3COOH(g) is heated to a constant temperature and allowed to reach equilibrium.
The equilibrium mixture contains 6.80 mol of CH3COOH(g)\text{CH}_3\text{COOH}(\text{g})CH3COOH(g), and the total pressure is 4.00 atm4.00\text{ atm}4.00 atm.
Determine the value of KpK_{\text{p}}Kp and give your answer to 3 significant figures.
Include an expression for KpK_{\text{p}}Kp and the units of KpK_{\text{p}}Kp in your answer.
Kp=…………………units………………… K_{\text{p}} = \dots\dots\dots\dots\dots\dots\dots \quad \text{units} \dots\dots\dots\dots\dots\dots\dots Kp=…………………units…………………The sealed flask in (a)(i) is then heated to a higher temperature at an increased pressure. The system is allowed to reach equilibrium again.
Explain why it is difficult to predict how these changes in reaction conditions affect the amount of (CH3COOH)2(g)(\text{CH}_3\text{COOH})_2(\text{g})(CH3COOH)2(g) formed at equilibrium.
Calcium sulfite decomposes or oxidizes under different conditions. In one experiment, sulfur dioxide, SO2\text{SO}_2SO2, reacts fully with oxygen to form a different oxide of sulfur, oxide B, as the only product.
Oxide B is collected and heated to 80.0∘C80.0^\circ\text{C}80.0∘C at a pressure of 102 kPa.
Under these conditions, oxide B is a gas that occupies a volume of 85.0 cm3 and has a mass of 0.236 g.
Calculate the molar mass of oxide B and suggest its molecular formula.
molar mass=………………… g mol−1 \text{molar mass} = \dots\dots\dots\dots\dots\dots\dots\text{ g mol}^{-1} molar mass=………………… g mol−1 molecular formula=………………… \text{molecular formula} = \dots\dots\dots\dots\dots\dots\dots molecular formula=…………………
