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Bonding

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Question 2

The boiling point of XeF4\text{XeF}_4XeF4​ (which sublimes at 117 °C) is significantly higher than the boiling point of SF4\text{SF}_4SF4​ (-38 °C).

Explain why these two compounds have different boiling points.

In your answer you should:

  • State the shape of each molecule and explain why each molecule has that shape.
  • Explain how the shape of each molecule influences its polarity and the type(s) of intermolecular forces present.
  • Explain why the boiling point of XeF4\text{XeF}_4XeF4​ is higher despite any differences in intermolecular force types.
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Bonding Questions

  1. A Level
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