The reaction between manganate(VII) ions and ethanedioate ions in acidic solution is represented by the following equation:
2MnO4−+5C2O42−+16H+→2Mn2++10CO2+8H2O 2\text{MnO}_4^- + 5\text{C}_2\text{O}_4^{2-} + 16\text{H}^+ \rightarrow 2\text{Mn}^{2+} + 10\text{CO}_2 + 8\text{H}_2\text{O} 2MnO4−+5C2O42−+16H+→2Mn2++10CO2+8H2OWhat volume, in dm3\text{dm}^3dm3, of 0.0800 mol dm-3 potassium manganate(VII) solution is required to completely oxidize 0.0500 mol of ethanedioate ions?
0.2500.2500.250
0.6250.6250.625
1.561.561.56
4.004.004.00