The equation for the reaction between aluminium and hydrochloric acid is
2Al(s)+6HCl(aq)→2AlCl3(aq)+3H2(g) 2\text{Al(s)} + 6\text{HCl(aq)} \rightarrow 2\text{AlCl}_3\text{(aq)} + 3\text{H}_2\text{(g)} 2Al(s)+6HCl(aq)→2AlCl3(aq)+3H2(g)What is the minimum mass, in mg, of aluminium (Ar=27.0A_{\text{r}} = 27.0Ar=27.0) needed to react completely with 45.0 cm3 of 0.800 mol dm-3 hydrochloric acid?
3.24×10−13.24 \times 10^{-1}3.24×10−1
3.24×1023.24 \times 10^23.24×102
9.72×1029.72 \times 10^29.72×102
2.92×1032.92 \times 10^32.92×103
79 exam-style questions on AQA A Level Chemistry Amount of substance, covering Relative atomic mass and relative molecular mass, The mole and the Avogadro constant, The ideal gas equation, Empirical and molecular formula, and Balanced equations and associated calculations. Each one has a worked solution and a mark scheme showing where the marks go.