What is the mole fraction of 2.0 g of a compound of relative molecular mass 100.0 dissolved in 30.0 g of a solvent of relative molecular mass 60.0?
1.0×10−21.0 \times 10^{-2}1.0×10−2
3.8×10−23.8 \times 10^{-2}3.8×10−2
4.0×10−24.0 \times 10^{-2}4.0×10−2
6.7×10−26.7 \times 10^{-2}6.7×10−2