Skip to content
MathsGenie logo
Open app

Course home

  1. A Level
  2. Biology OCR A
  3. Question bank

Practical skills assessed in a written examination

EasyMediumHard
12345678910111213141516171819202122232425262728293031323334353637383940414243444546474849505152535455
Question 53

In the fruit fly Drosophila melanogaster, two genes control eye color and wing shape:

  • For eye color, the allele for red eyes (EEE) is dominant to the allele for sepia eyes (eee).
  • For wing shape, the allele for normal wings (VVV) is dominant to the allele for vestigial wings (vvv).

A geneticist crossed two Drosophila flies that were heterozygous for both genes (EeVvEeVvEeVv). The expected phenotypic ratio of their offspring under the hypothesis of independent assortment is 9:3:3:19:3:3:19:3:3:1.

The geneticist obtained a total of 320320320 offspring from this cross. The observed numbers for each phenotype were:

  • Red eyes, normal wings: 171171171
  • Sepia eyes, normal wings: 696969
  • Red eyes, vestigial wings: 545454
  • Sepia eyes, vestigial wings: 262626
a.

Use the chi-squared formula

χ2=∑(O−E)2E \chi^2 = \sum \frac{(O - E)^2}{E} χ2=∑E(O−E)2​

to calculate the χ2\chi^2χ2 value for these data.

[3]
b.

State the number of degrees of freedom for this test.

[1]
c.

Using the critical values table below (for p=0.05p = 0.05p=0.05), determine whether the null hypothesis (that there is no significant difference between the observed and expected results) should be accepted or rejected, and explain your answer.

Degrees of freedomCritical value (p=0.05p = 0.05p=0.05)
13.84
25.99
37.82
49.49
[2]

Practical skills assessed in a written examination Questions

  1. A Level
  2. /Biology
  3. /Practical skills assessed in a written examination