The gene coding for the DNA polymerase enzyme in a newly isolated marine bacteriophage is 8.568 kilobases8.568\text{ kilobases}8.568 kilobases in length. In this bacteriophage, the DNA double helix makes one complete helical turn every 10.2 base pairs10.2\text{ base pairs}10.2 base pairs. Every complete helical turn is 3.4 nm3.4\text{ nm}3.4 nm in length.
Use this information to calculate the length in micrometres (μm\mu\text{m}μm) of this DNA polymerase-coding gene. Give your answer to 3 significant figures.
